3x^2-6x-504=0

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Solution for 3x^2-6x-504=0 equation:



3x^2-6x-504=0
a = 3; b = -6; c = -504;
Δ = b2-4ac
Δ = -62-4·3·(-504)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-78}{2*3}=\frac{-72}{6} =-12 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+78}{2*3}=\frac{84}{6} =14 $

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